Thermodynamics熱力學
Chapters章節  /  04 Process / Flow Devices04 過程 / 流動裝置

Flow Devices & Isentropic Efficiency流動裝置與等熵效率

The steady-flow energy equation comes alive in real hardware. Each device keeps only the terms that matter — and each real device falls short of its ideal, isentropic best. Here we work through nozzles, turbines, compressors, throttles, and heat exchangers, then measure the gap with isentropic efficiency.

SFEE device explorer Isentropic-efficiency lab
Process · Overview過程 · 總覽

What you'll be able to do本章學習成果

  • Reduce the steady-flow energy equation for each common device by dropping negligible terms.
  • Size nozzles, turbines, compressors, throttles, and heat exchangers from inlet/exit states.
  • Define and evaluate isentropic efficiency for turbines, compressors, pumps, and nozzles.
  • Locate the ideal (isentropic) exit state and quantify the loss to irreversibility.

Builds directly on the general balance from Control-Volume Analysis.

Key equations重要公式

Nozzle噴嘴
$(h_1-h_2) = (V_2^2-V_1^2)/2$
Turbine / compressor渦輪機 / 壓縮機
$\dot W/\dot m = h_1 - h_2$
Turbine efficiency渦輪機效率
$\eta_t = (h_1-h_2)/(h_1-h_{2s})$
Compressor efficiency壓縮機效率
$\eta_c = (h_{2s}-h_1)/(h_2-h_1)$
Devices裝置

Nozzles & diffusers噴嘴與擴散器

A nozzle speeds a flow up at the expense of pressure; a diffuser does the reverse. Both have no work and usually negligible heat transfer and potential-energy change, so the SFEE reduces to a trade between enthalpy and kinetic energy:

$$ 0 = (h_1 - h_2) + \frac{V_1^2 - V_2^2}{2} $$
Eq. 4.21

A drop in enthalpy appears as a rise in velocity. (Subsonic nozzles narrow in the flow direction; supersonic ones widen — the reverse for diffusers.)

Devices裝置

Turbines

A turbine develops shaft work as fluid expands through its blades. With negligible heat transfer and KE/PE changes, the enthalpy drop becomes work:

$$ \frac{\dot W_{cv}}{\dot m} = h_1 - h_2 $$
Turbine
Devices裝置

Compressors & pumps

A compressor (gas) or pump (liquid) does work on the fluid to raise its pressure. Same reduced equation as the turbine, with the work input sign reversed:

$$ \frac{\dot W_{cv}}{\dot m} = h_1 - h_2 \;\;(<0,\text{ work in}) $$
Compressor / pump

For a pump handling a nearly incompressible liquid, $w_p \approx v(p_2 - p_1)$ — much smaller than equivalent gas-compression work.

Devices裝置

Throttling devices

A throttle (valve or porous plug) drops pressure with no work and negligible heat or KE change, so enthalpy is conserved:

$$ h_2 = h_1 $$
Eq. 4.22

For an ideal gas $h = h(T)$, so $T$ is unchanged; for real fluids the temperature usually drops sharply — the basis of refrigeration and of the throttling calorimeter used to measure steam quality.

Devices裝置

Mixing chambers & heat exchangers

In a mixing chamber streams combine directly; in a heat exchanger they exchange heat through a wall without mixing. With no work and no external heat loss, the energy carried in by the streams equals that carried out:

$$ \sum_i \dot m_i h_i = \sum_e \dot m_e h_e $$
Eq. 4.18

Mass balances on each stream close the problem — e.g. a condenser relates the cooling-water flow to the steam flow.

Interactive互動

SFEE device explorerSFEE 裝置探索器

Pick a device and the schematic grays out the energy terms that drop, leaving the reduced equation. Then drive the sliders (air as ideal gas) to compute the headline result — exit velocity, power, or the throttle's constant-enthalpy outcome.

Air as ideal gas, $c_p = 1.005$ kJ/kg·K. Each device keeps only its essential terms.

Reality現實情況

Isentropic efficiency等熵效率

Adiabatic devices can only reach exit states with $s_2 \ge s_1$, so the best possible exit is the isentropic one (state 2s) at the same exit pressure. Isentropic efficiency measures how close a real device comes. For a turbine it is the actual work as a fraction of the ideal:

$$ \eta_t = \frac{h_1 - h_2}{h_1 - h_{2s}} $$
Eq. 6.46

For a compressor or pump the ideal is the minimum work, so the ratio inverts:

$$ \eta_c = \frac{h_{2s} - h_1}{h_2 - h_1} $$
Eq. 6.48

A nozzle efficiency compares actual to isentropic exit kinetic energy. In every case the irreversibility shows up as the actual state lying to the right of 2s on a T–s or Mollier diagram. (The entropy basis for $s_2 \ge s_1$ is developed in Entropy.)

Interactive互動

Isentropic-efficiency lab

Expand or compress air between two pressures at a chosen isentropic efficiency. The ideal path (1→2s) is vertical — constant entropy; the actual path (1→2) leans right by exactly the entropy generated. Lower the efficiency and watch the work and exit temperature respond.

Air as ideal gas, $c_p = 1.005$ kJ/kg·K, $k = 1.4$.

Worked example範例

Isentropic turbine efficiency渦輪機等熵效率

Example範例 Rating a real turbine評估實際渦輪機性能

Given: steam enters a turbine at $h_1=3150$ kJ/kg; isentropic expansion to the exit pressure would reach $h_{2s}=2300$ kJ/kg; the measured work is 680 kJ/kg.

Find: the isentropic efficiency.

Solution. $$\eta_t=\frac{h_1-h_2}{h_1-h_{2s}}=\frac{680}{3150-2300}=\frac{680}{850}=0.80\ (80\%).$$ The real expansion delivers 80% of the ideal work; the rest is lost to irreversibility ($s_2>s_1$).