What you'll be able to do本章學習成果
- Reduce the steady-flow energy equation for each common device by dropping negligible terms.
- Size nozzles, turbines, compressors, throttles, and heat exchangers from inlet/exit states.
- Define and evaluate isentropic efficiency for turbines, compressors, pumps, and nozzles.
- Locate the ideal (isentropic) exit state and quantify the loss to irreversibility.
Builds directly on the general balance from Control-Volume Analysis.
Key equations重要公式
Nozzles & diffusers噴嘴與擴散器
A nozzle speeds a flow up at the expense of pressure; a diffuser does the reverse. Both have no work and usually negligible heat transfer and potential-energy change, so the SFEE reduces to a trade between enthalpy and kinetic energy:
A drop in enthalpy appears as a rise in velocity. (Subsonic nozzles narrow in the flow direction; supersonic ones widen — the reverse for diffusers.)
Turbines
A turbine develops shaft work as fluid expands through its blades. With negligible heat transfer and KE/PE changes, the enthalpy drop becomes work:
Compressors & pumps
A compressor (gas) or pump (liquid) does work on the fluid to raise its pressure. Same reduced equation as the turbine, with the work input sign reversed:
For a pump handling a nearly incompressible liquid, $w_p \approx v(p_2 - p_1)$ — much smaller than equivalent gas-compression work.
Throttling devices
A throttle (valve or porous plug) drops pressure with no work and negligible heat or KE change, so enthalpy is conserved:
For an ideal gas $h = h(T)$, so $T$ is unchanged; for real fluids the temperature usually drops sharply — the basis of refrigeration and of the throttling calorimeter used to measure steam quality.
Mixing chambers & heat exchangers
In a mixing chamber streams combine directly; in a heat exchanger they exchange heat through a wall without mixing. With no work and no external heat loss, the energy carried in by the streams equals that carried out:
Mass balances on each stream close the problem — e.g. a condenser relates the cooling-water flow to the steam flow.
SFEE device explorerSFEE 裝置探索器
Pick a device and the schematic grays out the energy terms that drop, leaving the reduced equation. Then drive the sliders (air as ideal gas) to compute the headline result — exit velocity, power, or the throttle's constant-enthalpy outcome.
Air as ideal gas, $c_p = 1.005$ kJ/kg·K. Each device keeps only its essential terms.
Isentropic efficiency等熵效率
Adiabatic devices can only reach exit states with $s_2 \ge s_1$, so the best possible exit is the isentropic one (state 2s) at the same exit pressure. Isentropic efficiency measures how close a real device comes. For a turbine it is the actual work as a fraction of the ideal:
For a compressor or pump the ideal is the minimum work, so the ratio inverts:
A nozzle efficiency compares actual to isentropic exit kinetic energy. In every case the irreversibility shows up as the actual state lying to the right of 2s on a T–s or Mollier diagram. (The entropy basis for $s_2 \ge s_1$ is developed in Entropy.)
Isentropic-efficiency lab
Expand or compress air between two pressures at a chosen isentropic efficiency. The ideal path (1→2s) is vertical — constant entropy; the actual path (1→2) leans right by exactly the entropy generated. Lower the efficiency and watch the work and exit temperature respond.
Air as ideal gas, $c_p = 1.005$ kJ/kg·K, $k = 1.4$.
Isentropic turbine efficiency渦輪機等熵效率
Example範例 Rating a real turbine評估實際渦輪機性能 ›
Given: steam enters a turbine at $h_1=3150$ kJ/kg; isentropic expansion to the exit pressure would reach $h_{2s}=2300$ kJ/kg; the measured work is 680 kJ/kg.
Find: the isentropic efficiency.
Solution. $$\eta_t=\frac{h_1-h_2}{h_1-h_{2s}}=\frac{680}{3150-2300}=\frac{680}{850}=0.80\ (80\%).$$ The real expansion delivers 80% of the ideal work; the rest is lost to irreversibility ($s_2>s_1$).